From: Krekoski Ross (firstname.lastname@example.org)
Date: Wed Mar 19 2008 - 21:20:43 MDT
Correct me if I'm wrong but doesn't the Bekenstein bound exhibit a more or
less intimate relationship with the size of the universe since its reliant
on lowest possible energy?
but aside from being mean...
Its a valid question, you can read a summary here that talks about it:
I dont know how much background in math you have but it gets into topography
On Thu, Mar 20, 2008 at 2:15 AM, Mike Dougherty <email@example.com> wrote:
> On Wed, Mar 19, 2008 at 4:10 PM, Matt Mahoney <firstname.lastname@example.org>
> > The model assumes that the set of states is isomorphic to N. Any real
> > implementation with finite memory must have finite subjective
> experience. All
> > implementations must have finite memory because the universe has a
> > bound of about 10^122 bits.
> I looked up Bekenstein bound on wikipedia (it's a start)
> "S=A/4 where A is the two-dimensional area of the black hole's event
> horizon in units of the Planck area, \hbar G/c^3."
> Can someone explain how a two dimensional area is used to measure the
> amount of information that can be stored in a 3 (or more) dimensional
> universe? (Or if this is too basic a question, simply email me
> off-list with some educational URLs)
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