From: Peter de Blanc (email@example.com)
Date: Mon Jun 23 2008 - 13:37:21 MDT
J. Andrew Rogers wrote:
> On Jun 23, 2008, at 11:27 AM, Peter de Blanc wrote:
>>> The focus should have been on the very first line, since that had no
>>> ambiguity: Exactly how does a machine output a copy of itself (with
>>> or without the counter)?
>> Like this:
>> ((lambda (x y)
>> (list x (list (quote quote) x) (+ y 1)))
>> (lambda (x y)
>> (list x (list (quote quote) x) (+ y 1)))) 0)
> Nothing is happening. I think you might have lost some state.
> J. Andrew Rogers
You need to run it in a scheme or lisp interpreter. I use PLT Scheme. It
outputs a copy of itself, except that the 0 at the end is now a 1.
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